2x^2+7x=63

Solution for 2x^2+7x=63 equation:

2x^2+7x=63

We move all terms to the left:

2x^2+7x-(63)=0

a = 2; b = 7; c = -63;
Δ = b2-4ac
Δ = 72-4·2·(-63)
Δ = 553
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{553}}{2*2}=\frac{-7-\sqrt{553}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{553}}{2*2}=\frac{-7+\sqrt{553}}{4}
$